Squaring the Circle
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Authors
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S. Ramanujan
DOI:
https://doi.org/10.18311/jims/1913/17732Abstract
Let PQR be a circle with centre 0, of Which a diameter is PR. Bisect P0 at H and let T be the point of trisection of OR nearer R. Draw TQ perpendicular to PR and place the chord RS = TQ.
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Published
1913-06-01
How to Cite
Ramanujan, S. (1913). Squaring the Circle. The Journal of the Indian Mathematical Society, 5(4), 132–132. https://doi.org/10.18311/jims/1913/17732
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Copyright (c) 1913 S. Ramanujan
This work is licensed under a Creative Commons Attribution 4.0 International License.
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